2y^2-28y=-80

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Solution for 2y^2-28y=-80 equation:


Simplifying
2y2 + -28y = -80

Reorder the terms:
-28y + 2y2 = -80

Solving
-28y + 2y2 = -80

Solving for variable 'y'.

Reorder the terms:
80 + -28y + 2y2 = -80 + 80

Combine like terms: -80 + 80 = 0
80 + -28y + 2y2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(40 + -14y + y2) = 0

Factor a trinomial.
2((4 + -1y)(10 + -1y)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(4 + -1y)' equal to zero and attempt to solve: Simplifying 4 + -1y = 0 Solving 4 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1y = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1y = 0 + -4 -1y = 0 + -4 Combine like terms: 0 + -4 = -4 -1y = -4 Divide each side by '-1'. y = 4 Simplifying y = 4

Subproblem 2

Set the factor '(10 + -1y)' equal to zero and attempt to solve: Simplifying 10 + -1y = 0 Solving 10 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1y = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1y = 0 + -10 -1y = 0 + -10 Combine like terms: 0 + -10 = -10 -1y = -10 Divide each side by '-1'. y = 10 Simplifying y = 10

Solution

y = {4, 10}

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